How to Properly Size a Pool Heat Pump

How to Properly Size a Pool Heat Pump

Without delving too much into scientific computations, the easiest way to size a pool heat pump is to use the manufacturer's information. Specifically, it takes 1.16 Wh to heat one liter of water by one degree Celsius. Using this data, we can determine that it requires 11.6 kWh to heat a 10,000-liter pool by one degree Celsius in an hour.

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To simplify the process further, we have created a table that estimates how quickly different sized pool heat pumps can raise the water temperature. This table helps you get an idea of the size of heat pump you might need for your pool before looking at specific models.

What Size Heat Pump Do I Need for My Pool?

How to Calculate Pool Heat Pump Sizes

Correct sizing of a pool heat pump ensures you maintain a comfortable temperature. For most people, the ideal temperature is around 29°C.

The main challenge in heating a pool is managing heat loss, not water volume. Pool water loses heat through evaporative cooling, which is a natural result of solar radiation. The heat pump's role is to replenish heat when cooling occurs.

Therefore, it is crucial to consider the rate of heat loss when choosing the appropriate pool heat pump size.

To calculate the estimated heat loss for a 6 m x 9 m pool with a water temperature of 24°C and an air temperature of 18°C, follow these steps:

• Subtract the air temperature from the water temperature: 24 - 18 = 6.
  
  

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• Multiply the temperature difference by the pool's surface area: 6 x 6 m x 9 m = 324.
• Multiply the result by the constant 0.027 to find the heat loss: 324 x 0.027 = 8.75 kW.

Thus, the heat loss rate for this pool is 8.75 kW.

For round-shaped pools (including oval-shaped pools), use the radius to calculate the surface area. With a pool heat pump size calculator, multiply the radius (r) by itself and then by the constant pi (3.14).

For example, for a rounded pool with a radius of 4.6 m under the same temperature conditions, the surface area is 4.6 x 4.6 x 3.14 = 66.44 m². Then, multiply the surface area by the temperature difference and the constant:

66.44 x 6 x 0.027 = 10.76 kW. The heat loss rate for this particular pool is 10.76 kW.

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